greciang03 greciang03
  • 01-05-2018
  • Mathematics
contestada

Multiply the following polynomials and write the resulting polynomial in descending order. (3x-8)(2x^2+4x-9)

Respuesta :

CastleRook
CastleRook CastleRook
  • 11-05-2018
The product of the polynomial will be:
(3x-8)(2x^2+4x-9)
=3x(2x^2+4x-9)-8(2x^2+4x-9)
=6x^3+12x^2-27x-16x^2-32x+72
=6x^3-4x^2-59x+72

The answer: 
6x^3-4x^2-59x+72

Answer Link
erato erato
  • 23-04-2019

Answer:

The resulting polynomial is:

[tex]6x^3-4x^2-59x+72[/tex]

Step-by-step explanation:

We have to multiply the polynomials:

[tex](3x-8)(2x^2+4x-9)\\\\=3x(2x^2+4x-9)-8(2x^2+4x-9)\\\\=6x^3+12x^2-27x-16x^2-32x+72\\\\=6x^3-4x^2-59x+72[/tex]

Hence, the resulting polynomial is:

[tex]6x^3-4x^2-59x+72[/tex]

Answer Link

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