We can write the equation for the solubility of the salt AB3 in water as AB3(s) ⇌ A3+ + 3B- Since 0.0690 mol AB3 dissolves in 1.00 L of water, the concentration of the ions in moles per liter is calculated as 0.0690 mol / 1.00 L water = 0.0690 M We now substitute this value to the solubility product Ksp expression Ksp = [A3+] [B-]^3 = (0.0690 M) (3 * 0.0690 M)^3 = 0.000612 Therefore, the Ksp of the salt is 6.12 x 10^-4.
