Given:
The refractive index of water, n₁=1.33
The angle of incidence, θ₂=40.0°
To find:
The angle of refraction.
Explanation:
The refractive index of the air is n₂=1
From the snell's law,
[tex]n_1\sin\theta_1=n_2\sin\theta_2[/tex]Where θ₂ is the angle of refraction.
On substituting the known values,
[tex]\begin{gathered} 1.33\sin40.0\degree=1\sin\theta_2 \\ \implies\theta_2=sin^{-1}(\frac{1.33\sin40.0\degree}{1}) \\ =58.75\degree \end{gathered}[/tex]Final answer:
The angle of refraction is 58.75°
