In the game of roulette, a player can place a $7 bet on the number 5 and have a 1/38 probability of winning. If the metal ball lands on , the player gets to keep the $7 paid to play the game and the player is awarded an additional $245. Otherwise, the player is awarded nothing and the casino takes the player's $7. What is the expected value of the game to the player? If you played the game 1000 times, how much would you expect to lose? Question content area bottom Part 1 The expected value is $ -0.37. the player would expect to lose about $
Since you would expect to win 1 in 38, the amount of times you will win in 1000 times is 1000 / 38 which is 26.32. therefore you would expect to lose 1000 - 26.32 times which is 973.68