Answer:
A) 1,600 J
Explanation:
Given:
Mass of ethanol, m = 60.0 g
Initial temperature, T1 = 70 C
Final temp, T2 = 43 C
To determine:
Heat (q) lost as ethanol is cooled
Formula:
The heat lost by a substance is given as:
[tex]q = -mc\Delta T = -mc(T2-T1)[/tex]
In the case of ethanol at 70 C, it exists as a liquid therefore, the specific heat capacity c = 1.0 J/gC
[tex]q = -60.0 g*1.0 J/gC*(43-70)C= 1620 J[/tex]
