Respuesta :

sarajevo

As we know that the value of trigonometric functions depends on the quadrant.

For example the value of sin in first quadrant is positive , in second quadrant its negative.

The value of sin, cos and tan can also be find using the trigonometric Table.

For the given problem, we can write from the trigonometric table that

[tex] sin(\pi)=0 [/tex]

sin([tex] \pi [/tex])=Sin([tex] \pi [/tex]-0) =Sin 0=0

Option C Sin([tex] \pi [/tex])=0

Also, using unit circle, Sin([tex] \pi [/tex])=0

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