keniiie
keniiie
01-07-2018
Mathematics
contestada
help with this blank question
Respuesta :
gmany
gmany
01-07-2018
[tex]i=\sqrt{-1}\to i^2=-1\\\\i^{15}=i^{1+14}=i^1\cdot i^{14}=i\cdot i^{2\cdot7}=i\cdot (i^2)^7=i\cdot(-1)^7=i\cdot(-1)=-i[/tex]
[tex]\text{Used:}\\\\a^n\cdot a^m=a^{n+m}\\\\(a^n)^m=a^{n\cdot m}[/tex]
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